If the applied voltage is of very high frequency, the reactance of C will be very low compared with R. Before launching into a mathematical analysis, we can deduce some of the electrical properties by visual inspection of the circuit. The single stage cut-off frequency was 994.7 kHz so, changing the CR time constant in the same proportion is the route to take.īasically, you need to start fiddling with the C value to bring \$f_C\$ up towards 1 kHz. The first circuit we shall analyze is that of an RC high-pass filter, as shown in the figure above. I'm sure you can convert that plain ordinary \$\omega\$ by taking the square root.Īnd, if you plug your values in for R and C you get a 3dB cut-off point of 372.26 Hz. Be careful, the input is not the Thevenin voltage.
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